Calculate the heat loss from a steel tank.

General Info

of lights

Light Heat (Btu/h)

of people

People Heat (Btu/h)

Total Light Heat (Btu/h)
Total People Heat (Btu/h)

Insulated
Tank Info
Radius (ft)
Height (ft)
Heat Loss (Bth/ft^2h)

of Units

Motor (kW)

Calculations
Tank Surface Area (ft^2)
Heat Loss (Btu/h)
Motor Heat (Btu/h)
Total Heat (Btu/h)

Calculation Reference

Heat Loss

Heat Flow from Steel Tanks

Thermal Analysis

To calculate the heat loss from a steel tank, you will need the tank's dimensions (radius and height), heat loss rate per unit surface area, and any additional heat sources such as lights and people. Here's how you can perform the calculations:

1. Calculate the tank surface area: The surface area of a cylindrical tank can be calculated using the formula:

   Surface Area = 2πrh + πr^2

   Where π is the mathematical constant pi (approximately 3.14159), r is the radius of the tank, and h is the height of the tank.

2. Calculate the heat loss from the tank: Multiply the tank surface area by the heat loss rate per unit surface area to obtain the heat loss in Btu/h. The heat loss rate per unit surface area can be provided as a value in Btu/(ft^2·h) or W/m^2.

   Heat Loss = Surface Area × Heat Loss Rate

3. Calculate the heat contribution from lights and people: If there are additional heat sources, such as lights or people, calculate their respective heat contributions in Btu/h. Multiply the number of lights by the heat generated by each light in Btu/h, and multiply the number of people by the heat generated by each person in Btu/h.

   Total Light Heat = Number of Lights × Light Heat Total People Heat = Number of People × People Heat

4. Calculate the total heat loss: Sum up the heat loss from the tank, the heat contribution from lights, and the heat contribution from people to obtain the total heat loss in Btu/h.

   Total Heat Loss = Heat Loss + Total Light Heat + Total People Heat

Note: Ensure that all the units used in the calculations are consistent (e.g., radius and height in the same unit, heat loss rate and surface area in the same unit).